10 thoughts on “MARTINGALE SYSTEM FOR ONLINE BLACKJACK – Responding to Comments”

1. The moment he has too look at the strategy card you know he doesn’t know what the heck he is doing

2. Your ignorance and stubbornness bothers me so much. You really have no idea what you're talking about. I'd WAGER that you'd never taken statistics and if you did you certainly didn't get an A. You are saying your other video was a Satire but yet here is two entirely new videos of you trying to justifying yourself, your bad play, your bad knowledge of the game and the statistics. I'm not trying to be mean here but you're actively avoiding myself and many many other professional players that are telling you that you're doing it wrong.
   For Martingale to really work you'd need to have an infinite bankroll or one twice as large as the casino is willing to accept in a single hand bet.

   Look the reason your statistics are wrong is simple. Each hand is played INDEPENDENTLY of each other hand. The probability of one hand does not affect the probability of the hands following it. In statistics we call this an INDEPENDENT EVENT. The math you are calculating in which a loss is less than two percent is incorrect. You have calculated a DEPENDENT event. One in which the event is affected by the one before it. When you do the math on a dependent event yes the chances would be less than two percent, but a hand in blackjack is a independent event. Meaning that after the first five loses your sixth hand would still have the same chance to win or lose as the other hands.

   Independent event calc for blackjack hand
   HAND 1 (1/2 = 50% chance of win or loss.) [approximately 50% chance of win/loss]
   HAND 2 (1/2 = 50% chance of win or loss.)
   HAND 3 (1/2 = 50% chance of win or loss.)
   HAND 4 (1/2 = 50% chance of win or loss.)
   HAND 5 (1/2 = 50% chance of win or loss.)
   HAND 6 (1/2 = 50% chance of win or loss.)

   Dependent event calculated for a blackjack hand (INCORRECT equation because blackjack hands are not dependent events)
   HAND 1 . (1/2 = 50% chance of win or loss.)
   HAND 2 . .5 (1/2 = 50% chance of win or loss.)
   HAND 3 . .5 x .5 (1/2 = 50% chance of win or loss.)
   HAND 4 . .5 x .5 x.5 (1/2 = 50% chance of win or loss.)
   HAND 5 . .5 x .5 x .5 x.5 (1/2 = 50% chance of win or loss.)
   HAND 6 . .5 x .5 x .5 x .5 x .5 (1/2 = 50% chance of win or loss.) = Less than two percent

   That is the correct way to calculate a dependent event 6 hands deep. But blackjack simply doesn't work that way as each hand is independent of the previous.
   If you still try to justify that the sixth hand is almost impossible to lose, well then my friend you ignorance is bliss.

   Even at that, something happening 2 times out of 100 is VERY FAR from impossible.

3. you really know nothing about poker either…your're so thick! Keep playing the martingale system then

4. His logic: people who know math better than him = haters.

5. 😂😂😂😂😂

6. You're wrong. Calculating probability of a sequence of events "as a whole" is fine – BEFORE the events. But you surely must know that if (for example) you lose 5 times in a row, and you are about to play a 6th game, the odds of winning that 6th game are NOT increased or affected in any way by the previous 5 losses. BUT if your system works, then who am I to argue. It's just your explanation that is wrong. I'm sure you're a millionaire by now 🙂

7. Gambling Charlie Zelenoff…

8. Is it just me or does anyone else think this guy might be simple?

9. At around 4:00 You are calling your viewers stupid?? WTF?? Clown

10. The outcome of prior events do not affect the win/loss probability of the current or subsequent event(s).

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