Posted in Roulette Strategy

LOW RISK HIGH REWARD WINNING ROULETTE STRATEGY!!

Roulette Strategy Video Information:

How to win big money at the Casino playing Roulette with new strategies tested at 9am every day. Use Martingale, outside bets, straight up, streets, six lines, splits, with bankrolls to fit every budget. Subscribers are encouraged to share their ideas and The Roulette Master will share and test them in new videos. Messages are answered promptly and are encouraged. Please Subscribe!! Turn on notifications!! Share content!!
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LOW RISK HIGH REWARD WINNING ROULETTE STRATEGY!!

10 thoughts on “LOW RISK HIGH REWARD WINNING ROULETTE STRATEGY!!”

  2. Looks like it would be fun if you didn’t care about losing the initial $200, but I can’t see you actually walking away with profit too often.

  4. This is literally a modification of the triple lux system from david at CEG dealer school

  5. slow down….you're a horrible teacher…..let us know exactly what you're doing … you seem like you're just playing for yourself and us watching along. Slow down and let us grasp what you're doing.

  9. I don’t know if you’ll see this but I don’t know how else to contact you…..Some of your demonstrations are good and some not….But here’s one you may want to show your audience…..Using 5 $ units. You will neutralize 14 numbers including the zeros…..By covering 2 double streets ..payout of 5 to 1. …….( 7-8-9-10-11-12) & 25-26-27-28-29-30) & then cover the (0-00 ) with a 1$ bet on each zero with payout of 35 to 1…So you will lose 6 five $ units or 30$ and make 35 $ on any zero for a 5$ profit….And whenever a single street bet wins you will make 11 units and lose five 5$ units for a profit of 6 units (30$) minus your two 1$ bets on the zeroes….So with 5 $ bets you’d profit 28$…And whenever a double street # shows up you would lose $2…..This will neutralize a HUGE section of the American roulette wheel of 7 numbers on opposite sides of the wheel and all side by side including the zeroes for a total of 14 neutralized numbers AND ALL THESE NUMBERS ARE SIDE BY SIDE….You will then have 24 numbers left to bet on which will be bet on as single streets ….but you will only cover 4 single streets at a time with 5$ bets…. So any time a # from a double street show up ,you will win 5 units and lose 5 units minus the two 1$ units units on the zeroes And if a 0-00 show up you will make $5…..Ans whenever a single street # shows up which is nor covered you will lose $32……So you make 5$ on any zero = +10$….Lose 2$ on 12 double street numbers = -24$….Lose -$32 on twelve number = – $384…..And make + 336 on any single street numbers …..So in 38 theoretical spins of the wheel if every number showed up one time the negative expectation would be – 408$. And the positive expectation would be + 346$….for a diff of – 62$…..in 38 spins…..
    This could be overcome by a betting strategy of 1-2-2-5-5-10-10-25-25-50 & don’t cover the zeroes until you up to 5$ bets ….And then try to win twice on whatever bet level you happen to be on…before going higher in you bets …..
    Anyway if you can understand this overall strategy ,Mabe you will put it out there.

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